good day folks.
I am installing the 500ff kit (upgraded to 100w and 12awg) as laid out/described in the DYI by DirtyDog.

My problem is the relay with the kit was defective so I went and installed the lights without the rely. I eventually bought a new relay but didn't notice the new relay was a 5 pin until I got home and ready to install. don't really want to deal with returning it as it was bought in different town and if I can use this one, I will.

Anyway... the new relay is laid out with 4 outside pins and a center pin. they are labeled:

87 - top
87 - center, on each side of this pin is a letter "L" and "H"
85 - right
86 - left
30 - bottom

thru research I know how to wire a 4 pin to the lights, switch, etc but not a 5 pin. If i leave the center pin empty what will the consequences be, if any?

 

the "definitions you have given don't really mean anything. I'm guessing that 2 of the pins are for the coil to switch the relay, the other three are common, normally closed (probably "L") and normally open (probably "H"). Use a volt/ohm meter and ring out the terminals, or possibly google a seach for that relay to identify the proper termination of the relay. As long as the relay meets the current demand, and I'm assuming that it has a 12v DC coil, there's no reason you can't use it. Just make good, clean, tight connections

 

5-pin relay uses pin 87a and 87b. Just ignore the center pin and you'll be fine.

 

I'll do as you say Ddog as it seems the easiest. I report on what happens. Thanks.

 

Single pole, double throw relay can be used in EVERY wire job where you'd use a single pole, single throw. It will work just fine, for your purposes just treat it like the center pin doesn't exist.

A little more reading to confuse you, LOL:

https://dodgeforum.com/forum/3rd-gen...nd-relays.html